The area of a rectangular meadow is 2,800m^2. A cow is tied at the centre of the meadow with the help of a rope of length 28m.PLZZZZ EXPLAIN WITH A DIAGRAM.
1) How much area of the meadow the cow will graze? Use π = 22/7
Answers
Answered by
2
-Since the Cow is tied at the centre
therefore,the cow will graze in a circular area
-Since the length of the rope=28m,
therefore, radius of the circular area=28m.
Area of the meadow ln which the cow will graze=πr^2
-Area=22/7*28*28
ar.=22*4*28=2464m^2
-therefore, The view will graze in the area of 2464m^2
therefore,the cow will graze in a circular area
-Since the length of the rope=28m,
therefore, radius of the circular area=28m.
Area of the meadow ln which the cow will graze=πr^2
-Area=22/7*28*28
ar.=22*4*28=2464m^2
-therefore, The view will graze in the area of 2464m^2
Answered by
0
Answer:
Sorry i don't no .....
please mark me branliset please
Similar questions