Question

The area of a rectangular mirror is 11 11/16 square feet. The width of the mirror is 2 3/4 feet. If there is a 5 foot tall space on the wall to hang the mirror, will it fit? EXPLAIN..

Answer 1

$area = 11 \frac{11}{16} sq \: feet \\ width = 2 \frac{3}{4} = \frac{11}{4} feet\\ length = \frac{area}{width} = \frac{ \frac{187}{16} }{ \frac{11}{4} } \\ length = \frac{187}{16} \times \frac{4}{11} = \frac{17}{4} \\ length= 4 \frac{1}{4} feet\\ now \: the \: space \: onwall \: is \: 5 \: feet \: and \\ \: 5 > 4 \frac{1}{4} \\ so \: the\: mirror \: can\: be \: hanged$