Question

the area of a rectangular paper is 4- x² then its dimentions are​

Answer 1

Answer:

The answer is $2+x$ and $2-x$

Step-by-step explanation:

Given area of the rectangular paper $=4-x^2$

                                                            $=2^2-x^2\\=(2+x)(2-x)$

And since we know that area of rectangle is $=\text{Product of side lengths}$

So side lengths or dimension of the paper are $2+x$ and $2-x$