Math, asked by alokkumarrairai, 1 year ago

The area of a rectangular Park is 1560 m square and its breadth is 24 M find the length and perimeter of the park also find the cost of fencing it at rupees 22.50 per metre

Answers

Answered by Anonymous
106
\textbf{ANSWER:}

Given that:

•Area of the field =》 1560 sq. m

•Breadth =》 24 m

To find:

▪Length

▪Perimeter

▪Cost of fencing at Rs. 22.5 per m

Solution:

Length = \frac{Area}{Breadth} \\ \\ = > \frac{1560}{24} \\ \\ = > 65 \: m

 \\ Perimeter = 2(l + b) \\ = > 2(65 + 24) \\ = > 2 \times 89 \\ = > 178 \: m



Cost of fencing = Perimeter × 22.5

=》Rs. 4005
_____________

⊙Length = 65 m

⊙Perimeter = 178 m

⊙Cost of fencing at Rs. 22.5 per m = Rs. 4005

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Answered by Anonymous
26

area of rectangle=1560m²

So, l×b=1560

l = 1560/b

 = 1560/24

 = 65m

Now,

perimeter= 2(l+b)

               =2(65+24)

              =178m

cost of fencing=perimeter×22.5

= 178×22.5

= 4005 rupees

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