Math, asked by asnutan, 11 months ago


The area of a rectangular park is 1560m
and its breadth is aum. Eind the
length and the perimeter of the
park.And also find the cost of fencing it at rupees 22.50 per metet​

Answers

Answered by Anonymous
0

area of rectangle=1560m²

l×b=1560

l = 1560/b

= 1560/24

= 65m

Now,

perimeter = 2(l+b)

= 2(65+24)

= 178m

Now,

cost of fencing=perimeter×22.5

= 178×22.5

= 4005 rupees

Answered by vienchiez
1

Answer:

=area of park =1560m²

=length×breadth=1560m²

=length×24m=1560m²

=length=1560m²/24m

=length=65m

Perimeter of park

=2(length+breadth)

=2(65m+24m)

=2×89m

=178m

Cost of fencing =Rs 22.50×178

=Rs 4005

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