Math, asked by darahiy, 11 months ago

the area of a rectangular Park is 2160 m square the length and breadth of the park are in the ratio 5 is to 3 find the cost of fencing the park at 25 rupees per metre

Answers

Answered by LuckyYadav2578
49
length and breadth are in ratio of 5:3
let length be 5x
and breadth be 3x

are of rectangle = L × B
2160= 15x ^2
x^2= 2160/15
x^2= 144
x=12

length = 5×12 =60
breadth =3×12=36

perimeter of rectangle = 2 (L+B)
= 2×(60+36)
=192 m

cost of fencing = 192 × 25 = Rs 4800

i hope its help ☆☆ :)
Answered by khushi2880
14
area of rectangular park = l×b=2160 m square
ratio of length and breadth = 5:3
let the length of park be = 5x
and the breadth of park be = 3x
so, 5x × 3x = 15x^2
15x^2 =2160m square
x^2 = 2160 ÷ 15
x^2 =
 \sqrt{144}
so, x^2 = 12^2
x = 12 m
length of park = 5x = 5× 12 = 60 m
breadth of park = 3x = 3× 12 =36 m

Perimeter of rectangular park = 2 ( l + b)
perimeter = 2 (60+36)
perimeter = 2 ×96 =192 m
cost of fencing per metre = 25 rupees
cost of fencing 192m = 192 × 25 = 4800 rupees


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