the area of a rectangular Park is 4100 m square and its breadth is 50 M find the cost of fencing it @ rupees 30 per metre
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Answered by
10
area = 4100 m^2
Breadth = 50 m
therefore length = 4100/50 = 82 m
perimeter = 2(l+b) = 2(50+82)= 264
therefore cost of fencing = 30*264 = Rs 7920
Breadth = 50 m
therefore length = 4100/50 = 82 m
perimeter = 2(l+b) = 2(50+82)= 264
therefore cost of fencing = 30*264 = Rs 7920
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Answered by
8
area of rectangular park=length×breadth
4100=l×50
l=4100÷50
l=82m
area to be fenced=2×(l+b)
=2×(82+50)
=2×132
=264m
cost of fencing=30×264
=7920rupees
4100=l×50
l=4100÷50
l=82m
area to be fenced=2×(l+b)
=2×(82+50)
=2×132
=264m
cost of fencing=30×264
=7920rupees
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