Question

The area of a rectangular Park which is 4om long
is same as a square park which is 6om wide.
find the perimeter of the suct angular Pack .​

Answer 1

Question :

The area of rectangular park which is 4m wide is same as a square park which have side as 6m. Find Perimeter of such that Rectangular park.

$\rule{150}{0.5}$

Answer :

As we know that :

• Area of Square = Side²
• Area of Rectangle = length*breadth

A.T.Q,

⇒Area of Square = Area of rectangle

⇒Side² = length * Breadth

⇒6² = 4 * Length

⇒Length = 36/4

⇒Length = 9

$\therefore$ Length of rectangle is 9 m

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Now, use formula for Perimeter of Rectangle

• Perimeter = 2(Length + breadth)

⇒ 2(length + breadth)

⇒Perimeter = 2(9 + 4)

⇒Perimeter = 2(13)

⇒Perimeter = 26

➠ Perimeter of Rectangular filed is 26 m

Answer 2

Solution

Given:-

• Width of rectangular park = 4 m
• Side of square park = 6 m

Find:-

• perimeter of rectangular park.

Explanation

Using Formula,

☛ Area of rectangle = Length × width

☛ Area of square = (Side)²

☛Perimeter of rectangular park = 2.[ length+width]

A/C to question,

( Area of rectangular same as the area of square park )

So,

➤▸ Area of rectangular park = area of square park

➤▸ Length × 4 = (6)²

➤▸ Length = 36/4

➤▸ Length = 9 m.

Hence:-

• Length of rectangular park = 9 m

Now, calculate perimeter of rectangular park .

➤▸ perimeter of rectangular park = 2.[9+4]

➤▸ perimeter of rectangular park = 2.[13]

➤▸ perimeter of rectangular park = 26 m

Thus:-

• perimeter of rectangular park = 26 m

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