Question

The area of a rectangular piece of cardboard is 38 sq.cm and its length is 9 cm. What is the width of the cardboard ?​

Answer 1

Answer:

Explanation:

Given :

• Area of a rectangular piece of cardboard is 38 cm^2.
• It's length is 9 cm.

To Find :

• The width of the cardboard, b.

Formula to be used :

• Area of rectangle = length × width

Solution :

★Width,

Area = length × width

⇒ 38 = 9 × width

⇒ Width = 38/9

⇒ Width = 4.2 cm

Hence, Width of the cardboard is 4.2 cm.

Know to more:

• Perimeter of rectangle = 2(l + b)
• Area of square = a^2
• Perimeter of square = 4 × a

Answer 2

Step-by-step explanation:

$\text{\Large\underline{\red{Question:-}}}$

● The area of a rectangular piece of cardboard is 38 sq.cm and its length is 9 cm. What is the width of the cardboard ?

$\text{\Large\underline{\orange{To\ find:-}}}$

● In this question we have to find the width of the cardboard.

$\text{\Large\underline{\green{Given:-}}}$

$\sf We\ have = \begin{cases} \rm{Area\ of\ rectangular\ piece\ of\ cardboard\ is\ 38cm^{2.}} \\ \\ \rm{Its\ length\ is\ 9cm.} \end{cases}$

$\sf\underline{\ddag\qquad Formula\ to\ be\ used \qquad\ddag}$

${\orange{\underline{\fbox{Area\ of\ rectangle\ =\ length\ ×\ breadth}}}}$

$\text{\Large\underline{\purple{Solution:-}}}$

$\sf \: \: \: \: \: : \implies {Area\ of\ rectangle\ =\ length\ \times\ breadth}$

$\sf \: \: \: \: \: : \implies {38\ =\ 9\ \times\ breadth}$

$\sf \: \: \: \: \: : \implies {Breadth\ =\ \cancel \dfrac{38}{9}}$

$\sf \: \: \: \: \: : \implies {\purple{\underline{\fbox{B\ =\ 4.2cm.}}}}\bigstar$

Hence:-

● The width of the rectangular cardboard is 4.2cm.

$\Large\sf\underline{\ddag\qquad More\ to\ know \qquad\ddag}$

● Area of square = a².

● Perimeter of the rectangle = 2(l + b).

● Perimeter of square = 4 × a.

● Area of parallelogram = Base × Height.

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