Math, asked by shubham68ks, 2 months ago

The area of a rectangular plot is 270 sq.m and its length is 18 m. If the cost of fencing the park by wire is Rs.25 per metre, find the total cost of fencing. *

Answers

Answered by shreyaju
4

Step-by-step explanation:

Area =144m

2

Length =16m

Breadth=

16

144

=9m

Perimeter =2(l+b)

=2(16+9)

=2(25)=50m

Cost =6×50=300Rs.

Answered by Anonymous
35

Given:

\\

  • The area of a rectangular plot is 270 sq.m.
  • and its length is 18 m.
  • the cost of fencing the park by wire is Rs.25 per metre.

 \\

To Find :

  • The total cost of fencing the field

 \\

Solution:

~here we have been providing with the area and the length of the rectangle respectively and we have to find the breadth of the rectangle with the given clues.

so, that we will find its perimeter which will be helpful in finding the total cost of fencing the rectangular field.

 {\purple {\underline {\frak{As\: we \: know \:that}}}}

 \\

 \star\blue{ \underline{ \boxed{ \pink{ \mathfrak{ area_{(rectangle)} = lenght \times breadth}}}}}

 \\

~ Now let's substitute the given values to find the breadth

\longrightarrow \sf \: area = l \times b \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \\ \longrightarrow \sf \: 270 = 18 \times b  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \\ \longrightarrow \sf \: b =\cancel\frac{270}{18}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \\ \longrightarrow \sf \: { \orange{ \underline{ \boxed{ \frak{breadth = 15m}}} \bigstar}}

 \\

✪ Hence, the breadth of the rectangle is 15m

 \\

~ Now, let's find its perimeter and then multiply it with the cost of fencing per meter

 \\

 {\purple {\underline {\frak{As\: we \: know \:that}}}}

 \\

 \star\blue{ \underline{ \boxed{ \pink{ \mathfrak{ perimeter_{(rectangle)}  = 2(lenght + breadth)}}}}}

 \\

~Let's substitute the values of length And breadth now

 \\

\longrightarrow \sf \: perimeter = 2(l + b)  \:  \:  \:  \:  \:  \:  \\  \\  \\ \longrightarrow \sf \: perimeter  = 2(15 + 18) \\  \\  \\ \longrightarrow \sf \: perimeter  = 2 \times 33 \:  \:  \:  \:  \:  \:  \:   \\  \\  \\  \longrightarrow \sf \: { \orange{ \underline{ \boxed{ \frak{ perimeter= 66m}}} \bigstar}} \:  \:  \:  \:  \:

 \\

✪ hence the perimeter of the rectangle is 66m

 \\

~Now, let's find the cost of fencing the rectangular field

 \\

{\large {\underline{\pmb{\frak{Cost \:Of\: Fencing;}}}}}

➠66 × 25 rupees

➠1650 rupees

Hence,

  • The Cost to fence the field is Rs. 1650

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