Question

The area of a rectangular plot is 4089/5 sq.m .If its breadth is 87/4m, find its length​

Answer 1

Given :

Area of the rectangular plot = 4089/5

Breadth of the rectangular plot = 87/4

To find :

Length of the plot

Solution:

Area of a rectangle = Length * Breadth

Area of a rectangluar plot = Length of the rectangular plot * Breadth of the rectangular plot

4089/5 = Length of the rectangular plot * 87/4

4089/5 divided by 87/4 = Length of the rectangular plot

(4089/5) * (4/87) = Length of the rectangular plot

(4089*4) / (87*5) = Length of the rectangular plot ( we can cancel 4089 and 87 , so we get 47)

(47*4) / 5 = Length of the rectangular plot

188/5 = 37.6

Therefore, the length of the rectangular plot will be 37.6 m

Answer 2

Answer :-

The length of the rectangular plot is $\sf{\dfrac{5452}{145}m \: \: or \: \: 37.6m}$.

Step-by-step explanation:

To Find :-

• The length of Rectangular plot.

★ Solution

Given that,

• Area of Rectangular plot = $\sf{\dfrac{4089}{5} \: {m}^{2}}$.
• Breadth = $\sf{\dfrac{87}{4}m}$.

We know,

Area of rectangle = lb,

Where,

• l = length
• b = Breadth.

Therefore,

$\sf{\longrightarrow \: Length \times Breadth = area}$

$\sf{\longrightarrow \: Length \times \dfrac{87}{4} = \dfrac{4089}{5}}$

$\sf{\longrightarrow \: length = \dfrac{4089}{5} \times \dfrac{4}{87}}$

$\sf{\longrightarrow \: Length = \dfrac{4089 \times 4}{5 \times 87}}$

$\sf{\longrightarrow \: Length = \dfrac{16356}{435}}$

$\sf{\longrightarrow \: Length = \cancel{ \dfrac{16356}{435}}}$

$\sf{\longrightarrow \: Length = \dfrac{5452}{145}m \: \: \: \: or \: \: \: \: 37.6m}$

Hence,

Length of Rectangular plot is 5452/145m or 37.6m.