Question

The area of a rectangular plot is 528 m^. The length of the plot ( in meters) is one more than twice it's width.


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Answer 1

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Answer 2

Area =528m

Area =528m 2

Area =528m 2

Area =528m 2 Let Breadth be b

Area =528m 2 Let Breadth be bThen length l=2b+1

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b 2 −32b+33b−528=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0So b=16

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2+b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0So b=16l=33.