Question

The area of a rectangular plot is 616 square metre and its breadth is 22m. Find the length of the plot and the cost of fencing at the rate of Rs 7.50 per metre. * Length = 28m ,cost of fencing = Rs700 Length = 24m, cost of fencing = Rs450 Length = 28 m ,cost of fencing =Rs 750​

Answer 1

Explanation:

$Area \: of \: the \: rectangular \: plot = 616m²$

$Breadth \: of \: the \: rectangular \: plot \\ = 22m$

WE KNOW THAT:

$Length \times Breadth = Area \: of \: the \: rectangle$

$2(Length + Breadth) = Perimeter \: of \: the \: rectangle$

$Let \: the \: length \: of \: the \: rectangle \: \\ be \: x.$

22x=616

x=616/22

x=28m

Therefore, the length of tbe rectangle is 28m

The perimeter of the rectangle:

=2(28+22)

=2×50

=100m

Cost of fencing=7.50Rs.

Total cost: 7.50×100

=750Rs

Therefore the perimeter of the rectangle is 750m

Answer 2

Answer:

$Explanation:</p><p></p><p>Area \: of \: the \: rectangular \: plot = 616m²Areaoftherectangularplot=616m²</p><p></p><p>\begin{gathered}Breadth \: of \: the \: rectangular \: plot \\ = 22m\end{gathered}Breadthoftherectangularplot=22m</p><p></p><p>WE KNOW THAT:</p><p></p><p>Length \times Breadth = Area \: of \: the \: rectangleLength×Breadth=Areaoftherectangle</p><p></p><p>2(Length + Breadth) = Perimeter \: of \: the \: rectangle2(Length+Breadth)=Perimeteroftherectangle</p><p></p><p>\begin{gathered}Let \: the \: length \: of \: the \: rectangle \: \\ be \: x.\end{gathered}Letthelengthoftherectanglebex.</p><p></p><p>22x=616</p><p></p><p>x=616/22</p><p></p><p>x=28m</p><p></p><p>Therefore, the length of tbe rectangle is 28m</p><p></p><p>The perimeter of the rectangle:</p><p></p><p>=2(28+22)</p><p></p><p>=2×50</p><p></p><p>=100m</p><p></p><p>Cost of fencing=7.50Rs.</p><p></p><p>Total cost: 7.50×100</p><p></p><p>=750Rs</p><p></p><p>Therefore the perimeter of the rectangle is 750m</p><p></p><p>$