Question

The area of a rectangular plot of breadth 50m is 3000 m2 . Find its perimeter.

Answer 1

Answer :

• perimeter of rectangular is 220m

Given :

• Area of rectangular = 3000m
• Breadth = 50m
• length = ?

To find:

• perimeter of rectangular

Solution:

• Area of rectangular is 3000m

As we know that :

• Area of rectangle = l × b

➙ Area of rectangle = l x b

➙ 3000 = l × 50

➙ l = 3000/50

➙ l = 60m

Length is 60m

Now we have to find the perimeter:

As we know that:

• perimeter of rectangle = 2(l + b)

where l is length (60m) and breadth is (50m)

➙ perimeter of rectangular= 2(l + b)

➙ 2 (length + breadth)

➙ 2 (60 + 50)

➙ 2 (110)

➙ 220m

Hence perimeter of rectangular is 220m

More Explanation:

• Perimeter of rectangle = 2(l + b)
• Area of rectangle = lb
• Diagonal of rectangle = √l² + b²

Answer 2

Correct Question-:

• The area of a rectangular plot of breadth 50m is 3000 m² . Find its perimeter.

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Rectangular \:plot\: =  220 m.}}}}}$
• $\underline{\boxed{\star{\sf{\blue{  Breadth \:of\:Rectangular \:plot\: =  60 m.}}}}}$

EXPLANATION-:

• $\frak{Given \:\: -:} \begin{cases} \sf{The\:area\:of\:Rectangular\:plot\:is\:= \frak{3000m²}} & \\\\ \sf{Breadth \:of\:Rectangular \:plot \:=\:\frak{50m}}\end{cases}$
• $\frak{Given \:\: -:} \begin{cases} \sf{The\:Perimeter \:of\:Rectangular\:plot\:\: } & \\\\ \sf{Length \:of\:Rectangular \:plot \:}\end{cases}$

Now ,

• $\underline{\boxed{\star{\sf{\blue{  Area\:of\:Rectangular\:plot\:=length \times breadth.}}}}}$

$\frak{Here \:\: -:} \begin{cases} \sf{The\:area\:of\:Rectangular\:plot\:is\:= \frak{3000m²}} & \\\\ \sf{Breadth \:of\:Rectangular \:plot \:=\:\frak{50m}}\end{cases}$

• $\implies{\sf{\large { 3000m² = 50 × length}}}$
• $\implies{\sf{\large { \frac{3000}{50} = length}}}$
• $\implies{\sf{\large { 60m = length}}}$

Now ,

• $\underline{\boxed{\star{\sf{\blue{  Breadth \:of\:Rectangular \:plot\: =  60 m.}}}}}$ _______[1]

Now ,

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Rectangular\:plot\:=2(length + breadth).}}}}}$

$\frak{Here \:\: -:} \begin{cases} \sf{The\:Length \:of\:Rectangular\:plot\:is\:= \frak{60m}} & \\\\ \sf{Breadth \:of\:Rectangular \:plot \:=\:\frak{50m}}\end{cases}$

• $\implies{\sf{\large { Perimeter_{Rectangle}= 2(50 + 60) }}}$
• $\implies{\sf{\large { Perimeter_{Rectangle}= 2(110) }}}$
• $\implies{\sf{\large { Perimeter_{Rectangle}= 220m }}}$

Then ,

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Rectangular \:plot\: =  220 m.}}}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{  Perimeter \:of\:Rectangular \:plot\: =  220 m.}}}}}$
• $\underline{\boxed{\star{\sf{\blue{  Breadth \:of\:Rectangular \:plot\: =  60 m.}}}}}$

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