Question

The area of a rectangular prayer hall is 300 m2. If the length of the hall

(in metres) is one more than twice its its breadth, then find the dimensions

of the prayer hall.

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Answer 1

The dimensions of the prayer hall is 25cm × 12 cm

We know, for a rectangle of length l and breadth b, its area is given as 'lb'.

Given that the length of the rectangle is one more than twice that of the breadth.

So, l = 2b + 1

As area = l×b

So, area now = (2b+1)×b = 2b²+b

Given, the area is 300m²

So, 2b²+b = 300

⇒ 2b²+ b - 300 = 0

⇒ 2b² - 24b + 25b - 300 = 0

⇒ 2b(b - 12) + 25(b - 12) = 0

⇒ (b-12)(2b+25) = 0

By zero product rule,

b = 12         [ b cant be negative, ie -25/2, as side cant be negative]

b = 12cm

So, l = 2b+1 = 2(12) +1

= 24 + 1

= 25cm

So, length = 25 cm and breadth = 12 cm.

Answer 2

please

Step-by-step explanation:

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