The area of a rectangular prayer hall is 300 m2. If the length of the hall
(in metres) is one more than twice its its breadth, then find the dimensions
of the prayer hall.
Answers
Given that, The area of a rectangular prayer hall is 300 m². The length of the hall is one more than twice its Breadth.
Need to find: The dimensions of the prayer hall.
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Let the Breadth of the Rectangular prayer hall be x m.
Length of the rectangular prayer hall be (2x + 1) m.
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- Area of the rectangular prayer hall is given that is 300 m². Comparing with Formula,
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Therefore,
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- By ignoring the negative value, because any side can't be negative. Taking, x = 12.
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Hence,
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- Length of the Hall, x = {2(12) + 1} = (24 + 1) = 25 m
- Breadth of the Hall, x = 12 m.
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Given
- Area of rectangular prayer hall = 300 m²
- Length of hall = one more twice its breadth
To find
- Length of hall
- Breadth of hall
Solution
Let the breadth of hall be x cm, then according to the question, length is one more twice its breadth, so length of hall is 2x + 1
Then, solving the problem with the formula of area of rectangle :-
- Area = Length × Breadth
- 300 = (2x + 1) × (x)
- 300 = 2x² + x
- 2x² + x - 300 = 0
- 2x² + 25x - 24x - 300 = 0
- x (2x + 25) - 12(2x + 25) = 0
- (x - 12) = 0 or (2x + 25) = 0
- x = 12 or x = -25/2
Since, the value of side of rectangle or any other figure like square, circle cannot be negative, we consider the positive value.
Hence, the value of x is 12
The dimensions are
Length :-
- (2x + 1)
- (2(12) + 1)
- 24 + 1
- 25
Hence, the length of the rectangular prayer hall is 25 m
Breadth :-
- (x)
- 12
Hence, the breadth of the rectangular prayer hall is 12 m
Verification
- Area = Length × Breadth
- 300 = 25 × 12
- 300 = 300
- L.H.S = R.H.S
Learn more
- Area of square = side × side
- Area of rectangle = 1/2 × base × height
- Area of parallelogram = base × height
- Area of trapezium = 1/2 h (sum of parallel sides)