Question

the area of a rhobmus is 180m^2 and one of its diagonal is 75m find t
he perimeter of rhombus ?



please hurry up ​

Answer 1

Answer:

A=pq

2

P=4a

a=p2+q2

2

Solving forP

P=2p2+4(A

p)2=2·752+4·(180

75)2≈150.30689m

Answer 2

Answer

$⟹p = 2 \sqrt{p {}^{2} + 4 (\frac{a}{p} ) {}^{2} } \\ ⟹p = 2 \sqrt{75 {}^{2} +h 4( \frac{180}{75}) {}^{2} } \\ ⟹p = 150.30</h2><p></p><h2>$

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