Question

the area of a rhombus having each side equal to 13cm and one of whose diagonals is 24cm​

Answer 1

Answer:

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Answer 2

Given: side = 13 cm and One diagonal = 24 cm

To find: area of a rhombus

Step-by-step explanation:

According to question

∴Diagonals bisects and cuts each other at $90^o$

Area of rhombus = $\frac{1}{2}\times d_1\times d_2$

applying Pythagoras formula

$12^2+h^2=13^2$

$h^2=169-144$

$h^2=25$

$h=\sqrt25$

$h=5$

Then,

$Diagonal =2h$

$=2\times5$

$=10$

Area = $\frac{1}{2} \times 24\times10$

        = $120$