Math, asked by nano35, 4 months ago

The area of a rhombus in which the length of diagonals are 24 cm and 32 cm is
pls tell quick​

Answers

Answered by doraemon2627
2

Answer:

Area of rhombus = 1/2 ^ 24^ 32 =384cm

Answered by KishanKumar0001
0

Answer:

384cm²

Step-by-step explanation:

Area Of Rhombus = (d1×d2) / 2

 \frac{(d1 \times d2)}{2} \\  =  \frac{24 \times 32}{2}  \\  = 384 {cm}^{2}

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