Question

The area of a rhombus is 100 sq. m. If one of the diagonal is 20 m, then the length of other diagonal is?​

Answer 1

Answer:

area of diagonal=1/2×d1×d2

100. = 1/2×20×d2

100. =10×d2

D2=100/10=10

10m Answer

hope you like my answer

Answer 2

Given

Area of rhombus is 100²m.

One of diagonal is 20m

To find

Length of other diagonal

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf{ \boxed{ \bold{ \: Area \: of \: Rhombus= \dfrac{D_{1 }\times D_{2}}{2} }}}$

Where ,D1 and D2 are two Diagonals of rhombus

$\sf \: Area \: of \: Rhombus= \dfrac{20 \times d2}{2}$

$\sf \longmapsto100 = \dfrac{20 \times d2}{2}$

Now,cross multiply to both sides:

$\sf \longmapsto20 \times D_{2 }= 100 \times 2$

$\sf \longmapsto20D_{2} = 200$

$\sf \longmapsto \: D_{2}= \dfrac{200}{20} = 10$

∴The length of other diagonal is$\bold{\red{ 10m}}$

Extra information=>

• A rhombus is a type of quadrilateral whose all sides are equal.
• Diagonals of rhombus bisects each other at right angle.
• opposite sides and angles are equal in a rhombus.

$\sf\bold{\star}$Perimeter of rhombus is 4a (a is side)