Question

The area of a rhombus is 106 cm² and one of its diagonals is 20 cm, calculate its perimeter. ​

Answer 1

Step-by-step explanation:

here area of rhombus =1/2*(products of its diagonals)

so, let the other diagonal be x

then area = 1/2*(20*x)cm^2=1/2*20x cm^2

=10x cm^2

but area = 106 cm^2 (given)

10x =106

=> x = 106/10 = 10.6 cm

so half of one diagonal =1/2 *20=10cm

and half of others diagonal =1/2*10.6=5.3cm

so, here side of rhombus is forming the hypotenuse of triangle

By Pythagoras theoram

(hypotenuse) ^2=(base) ^2+(perpendicular) ^2

=(100+28.09)

=hypotenuse =√128.09

=38.09cm

now perimeter =4*side

=4*38.09=152.36cm

hope it helps

plz mark me as brainliest