Question

the area of a rhombus is 1080 m square and one of its diagonal is 72 M what is the perimeter of the Rhombus

Answer 1

Area = 1080 m²

One diagonal = 72m

Define x:

Let the other diagonal be x

Solve x:

Area = 1/2 (diagonal 1 x diagonal 2)

1080 = 1/2 (72x)

1080 = 36x

x = 30 m

Find the length of the rhombus:

(1/2 diagonal 1)² + (1/2 diagonal 1)² = Length²

Length² = ( 1/2 x 72 )² + (1/2 x 30)²

Length² = 19=296 + 225

Length² = 1521

Length = √1521

Length = 39 cm

Find the perimeter:

Perimeter = 4 x Length

Perimeter = 4 x 39

Perimeter = 156 cm

Answer: The perimeter of the Rhombus is 156 cm

Answer 2

Hi.guys now get your answer.....

The area of a rhombus = 1080m

So, 1/2×D1 ×D2 = 1080m.

1/2 × 72 × D2 = 1080.

36 × D2 = 1080

then D2 = 1080÷36 = 30

so,the length of other diagonal = 30.
on solving. we gets length of side. of rhombus = 39m

so, perimeter of rhombus= 4×39=156m

..............Thanks happy to help you...........