the area of a rhombus is 1080 metre square and one of its diagonals is 72 M what is the perimeter of the Rhombus
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Let second diagonal be x
Area of rhombus=1/2×d1×d2
1080=1/2×72×x
x=1080/36
x=3om
By Pythagoras theorem the side is39m
Perimeter of rhombus=4×s
=4×39
156m
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Area of rhombus=1/2×d1×d2
1080=1/2×72×x
x=1080/36
x=3om
By Pythagoras theorem the side is39m
Perimeter of rhombus=4×s
=4×39
156m
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