Question

The area of a rhombus is 120 cm2. If one of its diagonals is 24 cm, find the length of the other diagonal.

Answer 1

See Brother..,

Rhombus has diagonals intersecting at 90°,

So, Let ABCD be a rhombus and O be the point of intersection of the diagonals.....

Then... First of all...

Area of rhombus=120cm^2

So,

1/2×product of its diagonals=120cm^2

So,

1/2×24cm×2nd diagonal=120cm^2

Then,

2nd diagonal=2×120/24=10cm

So here begins the solution...

Now,

AO=1/2 of AC=1/2×24cm=12cm... (1)

And,

BO=1/2 of BD=1/2×10cm=5cm.... (2)

Now In triangle AOB.... By Pythogoras theorem,

AB^2=AO^2+BO^2

AB=√12^2+5^2

AB=√144+25

AB=√169=13

So eac side of rhombus is 13cm....

Please like if u get it.....

Answer 2

Answer:

The length of other diagonal is 10 cm.

Hope this helps

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