Question

the area of a rhombus is 120 sq. cm . one of its diagnoals is 24 cm . find the other diagnoal and it's perimeter . what is the distance between the parellel sides of the rhombus ​

Answer 1

Area of rhombus =1/2*d1*d2

120=1/2*24*d2

d2= 120*2/24

d2= 10 cm

Sides of rhombus

a = √d12 + d22/2

a = 41.2310563

Perimeter

P = 4a = 164.924225

Formula of rhombus side in terms of area and height:

a = S/h

Then distance between the parallel sides of the rhombus = 120/41.2310563

h = 2.91043147 cm