Question

The area of a rhombus is 16 cm^2 and the length of one of its diagonal is 4 cm. Calculate the length of other the diagonal.

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Answer 1

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$\huge\tt{GIVEN:}$

• Area of a Rhombus is 16 cm²
• The length of One of the diagonals is 4 cm

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$\huge\tt{TO~FIND:}$

• Length of other diagonal

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$\huge\tt{SOLUTION:}$

⇒Area of rhombus = ½ × d¹ × d²

⇒ 16 = ½ × 4 × d2

⇒ d² = 32/4

⇒ d² = 8 cm

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Answer 2

Gɪᴠᴇɴ :-

• Area of Rhombus = 16 cm²

• One diagonal = 4 cm

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ᴛᴏ ғɪɴᴅ :-

• Length of other diagonal

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sᴏʟᴜᴛɪᴏɴ :-

Let the length of other diagonal be 'x'cm

Now,

We know that,

$Area \: of \: Rhombus \: = \frac{1}{2} \times Product \: of \: its \: Diagonals$

So,

Put all the given values in it, we get,

$\implies \: 16 = \frac{1}{2} \times 4 \times x \\ \\ \implies \: 16 = \frac{4x}{2} \\ \\ \implies \: 16 = 2x \\ \\ \implies \: x = \frac{16}{2} = 8cm$

Hence,

➨ Length of other diagonal = 8 cm