Question

The area of a rhombus is 16 cmsq. . If the length of one diagonal is 4 cm, find the length of the other diagonal

Answer 1

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

Given thαt,

• The αreα of α rhombus is 16 cm².
• If the length of one diαgonαl is 4 cm.

We need to find the length of the other diαgonαl.

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Let the other diagonal be x.

We know thαt,

$\large{\boxed{\sf{\orange{ Area_{(rhombus)} = \dfrac{1}{2} \times d_1 \times d_2}}}}$

• Substitute the values.

$\longrightarrow{\sf{ 16 cm^{2} = \dfrac{1}{2} \times 4cm \times x\:cm}}$

$\longrightarrow{\sf{ 16 cm^{2} = \dfrac{1}{\cancel{2}} \times \cancel{4}cm \times x\:cm}}$

$\longrightarrow{\sf{ 16 cm^{2} = 2cm \times x\:cm}}$

$\longrightarrow{\sf{ \dfrac{16 cm^{2}}{2cm} =x\:cm}}$

$\large{:}\implies{\boxed{\sf{\orange{x = 8cm}}}}$

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Answer 2

Answer:

g

Step-by-step explanation: