The area of a rhombus is 192 sq. m. If one of its diagonal is 16 m. Then the length of other diagonal is :
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Shinchanboss
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Hello Mate!
Let construct a rhombus with diagonal of 16 cm and d2
Area = 1/2 × d1 × d2
96 cm^2 = 1/2 × 16 cm × d2
96 cm^2 = 8 cm × d2
96 cm^2 / 8 cm = d2
12 cm = d2
Now half the diagonals to make a small triangle AOB
16/2 = 8 cm
12/2 = 6 cm
Hence side are length of 10 cm
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Step-by-step explanation:
Area of rhombus= 192 sq.m.
Diagonal (d1)=16m
Area = d1+d2/2
196= 16+ d2/2
196×2=16+d2
196×2/16= d2
392/16=d2
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