Math, asked by manemanisha85423, 2 months ago

The area of a rhombus is 192 sq. m. If one of its diagonal is 16 m. Then the length of other diagonal is :​

Answers

Answered by mansurisoaib726
5

Answer:

Answer

4.0/5

135

Shinchanboss

Genius

3K answers

2.8M people helped

Hello Mate!

Let construct a rhombus with diagonal of 16 cm and d2

Area = 1/2 × d1 × d2

96 cm^2 = 1/2 × 16 cm × d2

96 cm^2 = 8 cm × d2

96 cm^2 / 8 cm = d2

12 cm = d2

Now half the diagonals to make a small triangle AOB

16/2 = 8 cm

12/2 = 6 cm

Hence side are length of 10 cm

Answered by tirutopusrivardhan
2

Step-by-step explanation:

Area of rhombus= 192 sq.m.

Diagonal (d1)=16m

Area = d1+d2/2

196= 16+ d2/2

196×2=16+d2

196×2/16= d2

392/16=d2

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