Question

the area of a rhombus is 216 cm sq if its one diagonal is 24 cmfind (i) the length of its other diagonal (ii) length of its side (iii)perimeter of rhombus

Answer 1

(1)area of rhombus = 1/2(D1 ×D2)
⇒216= 1/2(24×D2)
⇒D2 = 18 cm
(2) as we know that diagonals bisect each other at 90°
so by phythagoras theorem,
side =√[(12)² + (9)²] = √(144 +81)= √225 = 15 cm
(3)perimeter = 4×side = 4×15 = 60 cm

Answer 2

1)area of rhombus = 216
area = 1/2 .d1 . d2
=1/2.24.d2=216
=18
2) (ab) sq = (ao) sq + (bo) sq                                                                                  =(ab) sq= 9sq + 12 sq
=ab sq = 225 
ab = root of 225
ab = 15
p = 4a
p= 4(15)
p=60 cm