Question

The area of a rhombus is 216 m2 and the length of one of its diagonals is 24 m. The length of the other diagonals of the rhombus will be:​

Answer 1

$area = \frac{1}{2} \times d_1 \times d_2 \\ \\ 216 = \frac{1}{2} \times 24 \times d_2 \\ \\ d_2 = 12cm$

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Answer 2

$\huge\underline\mathrm{Your\:Answer}$

Given,

• Area of rhombus = 216m²
• Length of one of its diagonal = 24 m

Find,

• Length of other diagonal of the rhombus = ?

Solution,

= $\mathtt{Area\:of\:rhombus\:given\:=\:216\:m^2}$

= $\mathtt{Length\:of\:one\:diagonal\:=\:24\:m}$

= $\mathtt{Length\:of\:other\:diagonal\:=\:?}$

= $\mathtt{Area\:of\:rhombus\:=\:{\frac {1}{2}×d_1×d_2}}$

= $\mathtt{216m^2\:=\:{\frac {1}{2}×24m×d_2}}$

= $\mathtt{\frac {216}{12}\:=\:d_2}$

= $\mathtt{18\:=\:d_2}$

$\sf{\therefore 18m\:is\:the\:other\:diagonal\:of\:rhombus}$

Thank You!!