Question

The area of a rhombus is 24 square centimetres and the length of one of

its diagonals is 8cm compute the following measurements of this rhombus

a. perimeter​

Answer 1

Answer:

60 cm

Step-by-step explanation:

Area of rhombus =

2

1

×D

1

×D

2

216=

2

1

×24×D

2

(1) D

2

=

12

216

=18

(2) Diagonals perpendicular bisector of each other

OA=DC=12 & DB=OD=9

AB

2

=12

2

+9

2

=144+81=225

AB=15cm

(3) perimeter =4x15=60cm

Answer 2

Answer:

area of rhombus =1/2 ×d1 × d2

=>the other diagonal is (24×2)/4=d2

d2=12

so side of rhombus =√((d1^2+d2^2)/4)=√52=a

so perimeter =4a =4√52 =8√13

so 8√13 is your answer