Question

the area of a rhombus is 240 cm^2 and one of the digonal is 16 cm. find the other digonal ​

Answer 1

$\huge\underbrace\mathcal\pink{anSwer}$

Let first diagonal = d1 = 16cm

and second diagonal = d2 = ?

We know that,

Area of rhombus = 1/2 × d1 × d2

=> 240 = 1/2 × 16 × d2

=> 240 = 8 × d2

=> 240/8 = d2

=> d2 = 30 cm

Hope this helps ✌✌✌

Answer 2

$\large{\underline{\underline{Given→}}}$

The area of a rhombus is 240 cm^2 and one of the diagonal is 16 cm. Find the other diagonal.

$\large{\underline{\underline{Solution→}}}$

Using the formula,

$A = \frac{pq}{2}$

Solving for p,

$p = 2 \frac{A}{q} = 2. \frac{240}{16} = 30 \: cm$

We get,

The Value of the other diagonal = 30cm

${\boxed{\boxed{\rm{\green{→\bar{30 cm}✔}}}}}$

Learn More:-

Area of rhombus = $\frac{d1 \times d2}{2}$

Diagonal d2 = $\sqrt{4 {a}^{2} - d {1}^{2} }$

Diagonal d1 = $\sqrt{4 {a}^{2} - d {2}^{2} }$