Question

the area of a Rhombus is 240 cm square and one of the diagonals is 16 cm. The length of the other diagonal is

Answer 1

area of a rhombus is equal to 1/2×diagonal 1 ×diagonal 2
240 =1/2×d×16
therefore d is 30 cm

Answer 2

$\textbf{Given Data :}$

$\longrightarrow\textrm{Area of Rhombus = 240 cm \rm{^2} }$

$\longrightarrow\textrm{Length of First Diagonal (d _1 ) = 16 cm}$

$\rule{315}{2}$

$\textrm{Area of Rhombus = 1/2 \times d _1 \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 1/2 \times 16 cm \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 16/2 cm \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 8 cm \times d _2 }$

$\longrightarrow\textrm{d _2 = 240 cm ^2 \div 8 cm = 30 cm}$

$\boxed{\therefore\textbf{ Length of Second Diagonal (d _2 ) = 30 cm}}$