Question

The area of a rhombus is 256 sq. Cm and one of its diagonals is twice the other in length. Then length of its larger diagonal is

Answer 1

$hey \: here$
$let \: the \: other \: d2 \: be \: x$
$d2= 2x$
A/Q

$area \: of \: rhombus = \frac{1}{2} \times d1 \times d2$

$256 = \frac{1}{2} \times x \times 2x$
${x}^{2} = 256$
$x = \sqrt{256}$
$x = 16$
$1st \: diagonal = 16cm$
$2nd \: diagonal = 16 \times 2 = 32cm$

Answer 2

Answer:

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