Math, asked by ariba345, 11 months ago

The area of a rhombus is 28 sq m. If it's perimeter is 28m,find the length of its altitude.​

Answers

Answered by diyanambiar
2

Answer:

A = 28

P = 28

therefore S = 7

A = bh

28 = 7 × h

h = 4

Answered by rajsinhasofttech2018
0

Answer:

56

Step-by-step explanation:

Given, Perimeter of Rhombus is 28 m.

Given, Perimeter of Rhombus is 28 m. We know that Perimeter of rhombus = 4 A (where A = side)

Given, Perimeter of Rhombus is 28 m. We know that Perimeter of rhombus = 4 A (where A = side)Therefore, P = 4A

Given, Perimeter of Rhombus is 28 m. We know that Perimeter of rhombus = 4 A (where A = side)Therefore, P = 4A 28 = 4A

Given, Perimeter of Rhombus is 28 m. We know that Perimeter of rhombus = 4 A (where A = side)Therefore, P = 4A 28 = 4A 28/4 = A

Given, Perimeter of Rhombus is 28 m. We know that Perimeter of rhombus = 4 A (where A = side)Therefore, P = 4A 28 = 4A 28/4 = A 7 = A

So, side of the Rhombus = 7 m

Now, Given Area of the Rhombus = 28 sq m.

Now, Given Area of the Rhombus = 28 sq m.we know that Area of Rhombus = 1/2 × Length of Altitude

Now, Given Area of the Rhombus = 28 sq m.we know that Area of Rhombus = 1/2 × Length of Altitude Therefore, 28sq m = 1/2 × Length

Now, Given Area of the Rhombus = 28 sq m.we know that Area of Rhombus = 1/2 × Length of Altitude Therefore, 28sq m = 1/2 × Length 28 × 2 = Length

56 = Length

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