Question

The area of a rhombus is 36 cm2 and the length of one of its diagonal is 6cm.The length of the second diagonal is

Answer 1

Answer:

12cm

Step-by-step explanation:

Area=36cm²

length of d1= 6 cm

length of d2 = d

Area of rhombus = 1/2 x d1 x d

36 = 1/2 x 6 x d

36 = 3d

d = 36/3

d = 12

∴ the length of second diagonal is 12 cm

Answer 2

Answer:

$\red\bigstar$ The length of the second diagonal is 12cm.

SOLUTION

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$\sf Area \; of \: the \: rhombus = \dfrac{1}{2} * d1*d2$

[Here,d1 and d2 are the two diagonals of the rhombus]

Here,

Area of the rhombus = 36 cm².

Also, let us assume that first diagonal (d1) = 6cm.

$\implies \sf 36 = \dfrac{1}{2} * 6* d2$

$\implies \sf 36 * 2 = 6* d2$

$\implies \sf 72 = 6 d2$

$\implies \sf d2 = \dfrac{72}{6}$

$\implies$ d2 = 12 cm.

∴ The length of the second diagonal , d2 = 12cm.

QUESTION (FOR PRACTICE)

Q.The area of a rhombus is 56 cm² . If the length of one of its diagonal is 16 , then length of the second diagonal is ?

Answer (For Verification) → The length of the second diagonal is 7 cm.