The area of a rhombus is 480cm² and one of its diagonals measures 48cm. find (i) the length of the other diagonal, (ii) the length of each of its sides, and (iii) it's perimeter
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Answer :
- Length of the other diagonal = 20cm
- Length of each of its sides = 26cm
- It's perimeter = 104cm
Given :
- The area of a rhombus is 480cm² and one of its diagonals measures 48cm.
To Find :
- The length of the other diagonal.
- Length of each of it's sides.
- It's perimeter.
Solution :
Here
- Area of a rhombus is 480cm².
- One of the diagonal measures 48cm.
As we know that
- Area of a rhombus is ½ × d1 × d2
Now
→ ½ × d1 × d2 = 480
→ ½ × 48 × d2 = 480
→ 24 × d2 = 480
→ d2 = 480/24
→ d2 = 20
Half of the two diagonals and side make a right triangle
- a² + b² = c²
Where
- a = d1/2
- b = d2/2
- c = side
Now
→ side² = (48/2)² + (20/2)²
→ side² = (24)² + (10)²
→ side² = 576 + 100
→ side² = 676
→ side = √676
→ side = 26cm
As we know that
- Perimeter of a rhombus is 4 × side
Now
→ Perimeter of the rhombus = 4 × side
→ Perimeter of the rhombus = 4 × 26
→ Perimeter of the rhombus = 104cm
Hence,
- Length of the other diagonal = 20cm
- Length of each of its sides = 26cm
- It's perimeter = 104cm
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