Question

the area of a rhombus is 48cm square. one of itd diagonals measures 8cm. what is rhe length of other digonal ​

Answer 1

Answer:

48=1/2(8)(d), d=12

Step-by-step explanation:

Area of a rhombus is 1/2(d1)(d2)

Answer 2

Given ,

First diagonal = 8 cm

Area of rhombus = 48 cm²

We know that ,

$\large \fbox{ \sf \fbox{Area \: of \: rhombus = \frac{1}{2} \times D_{1} \times D_{2} }}$

$\sf \implies 48 = \frac{1}{ \cancel2} \times \cancel 8 \times D_{2} \\ \\\sf \implies D_{2} = \frac{48}{4} \\ \\\sf \implies D_{2} = 12 \: \: cm$

Hence , 12 cm is the required value of other diagonal