Question

The area of a rhombus is 540 cm2 and the length of one of its diagonals is 4.5 dm. What is the distance from the point of intersection of the diagonals to a side of the rhombus?

Answer 1

Answer:

$area \: of \: rhombus \: = \frac{d1 \times d2}{2} \\ where \: area \: = 540 \\ d1 = 4.5 \\ d2 \: = we \: have \: to \: find = ? \\ 540 = \frac{4.5 \times d2}{2} \\ d2 = \frac{2 \times 540}{4.5} \\ = 240cm$