Question

The area of a rhombus is 56m sq . if its perimeter is 28m . find its altitude.​

Answer 1

Answer:

area of Rhombus =56m²

perimeter =28m

altitude=Height =?

area of rhombus = base×height

sides of rhombus=28÷4=7(as the sides of rhombus are equal)

Then,A=Base×height

56=7×h

h=56÷7

h=8m

Answer 2

Given :

The area of a rhombus is 56m sq . perimeter is 28m .

To Find :

Altitude of the rhombus

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

Formula :

$\bold{\boxed{Area \: of \: Rhombus = \frac{d1 \times d2}{2} (d = diagonal)}}$

$= > Area \: of \: rhombus = 56 {m}^{2}$

Perimeter of Rhombus =28m

$Perimeter \: of \: Rhombus = 4 \times side$

$= > 4s = 28m$

$= > s = \frac{28}{4} = 7m$

Hence ,the sides of Rhombus is 7m each as all sides are equal of a rhombus.

$Altitude \: of \: a \: rhombus \: = {\green{\frac{Area}{Base} }}$

$= \frac{56}{7} = {\red{8m}}$

Therefore, altitude of rhombus is $\bold{\red{8m}}$

Some properties of Rhombus:

• All sides of rhombus are equal
• opposite sides of a rhombus are equal and parallel
• Opposite angles are equal
• Diagonal bisect each other at 90° and adjacent angles having sum equal to 180°

Other Related Formulas :

$\bold{\boxed{Area \: of \: square = {(side)}^{2}}}$

$\bold{\boxed{Area \: of \: triangle = \frac{1}{2} \times b \times h}}$

$\bold{\boxed{Area \: of \: circle = \pi {r}^{2} }}$

$\bold{\boxed{Area \: of \: rectangle = length \times breadth}}$