Question

The area of a rhombus is 56m sq . if its perimeter is 28m . find its altitude.​

Answer 1

Answer:

Altitude of the rhombus is 8m.

Step-by-step explanation:

Perimeter of the rhombus is 28m

∴ Each side = $\frac{28}{4} m = 7m$

If the altitude of the rhombus is h meters, then:

$7hm = 56 m^2$

∴ h = $\frac{56}{7} m$ = 8m

Answer 2

Given :

The area of a rhombus is 56m sq . perimeter is 28m .

To Find :

Altitude of the rhombus

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

Formula :

$\bold{\boxed{Area \: of \: Rhombus = \frac{d1 \times d2}{2} (d = diagonal)}}$

$= > Area \: of \: rhombus = 56 {m}^{2}$

Perimeter of Rhombus =28m

$Perimeter \: of \: Rhombus = 4 \times side$

$= > 4s = 28m$

$= > s = \frac{28}{4} = 7m$

Hence ,the sides of Rhombus is 7m each as all sides are equal of a rhombus.

$Altitude \: of \: a \: rhombus \: = {\green{\frac{Area}{Base} }}$

$= \frac{56}{7} = {\red{8m}}$

Therefore, altitude of rhombus is $\bold{\red{8m}}$