Question

• The area of a rhombus is 600 sq. cm. If its one diagonal is 40 cm, ſind:
(1) length of its other diagonal,
(1) length of its side,
(111) perimeter of the rhombus.​

Answer 1

Answer:

Step-by-step explanation:

We know that,

Area of rhombus = 1/2 x product of diagonals

600 = 1/2 x 40 x d

600x2/40=d

d = 30cm

AB = 30/2=15cm

BC=40/2= 20cm

Answer 2

Step-by-step explanation:

(I)area of rhombus = 1/2 d1×d2 (d is diagonal)

600=1/2*40*d2

d2=30

(ii)diagonal of rhombus bisect each other so the lines od=15 and oc=20 as given in the picture above

diagonal of rhombus also bisect then at 90degree so here we can apply Pythagoras theoram

so dc^2=od^2+oc^2

dc^2=15^2+20^2

=25. so the length of side is 25cm

(iii)perimeter of rhombus is 4×side

25×4=100