The area of a rhombus is 64 sqmt, ,its perimeter is 32mt, find the altitude
Answers
Answered by
0
perimeter=sum of all sides
32mt=4s
s=32/4
s=8m
a rhombus is a modified parallelogram
therefore,area=bXh
64sqmt=8mXh
h=64/8
=8mt
therefore the altitude is 8 mt
32mt=4s
s=32/4
s=8m
a rhombus is a modified parallelogram
therefore,area=bXh
64sqmt=8mXh
h=64/8
=8mt
therefore the altitude is 8 mt
Answered by
1
Perimeter: 32m ⇒side=32/4=8m
Rhombus is a parallelogram having all sides equal,
so area of parallelogram:baseXaltitude
64m²=8mXaltitude
⇒altitude=64/8=8m
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