Math, asked by spamingbeaty35, 3 months ago

The area of a rhombus is 72 cm². If the perimeter is 32 cm, find its altitude.​

Answers

Answered by Anonymous
14

Given: the area of a rhombus is 72 cm². And the Perimeter is 32 Cm.

Need to find : The altitude of the rhombus.

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As we know that :-

Perimeter ( rhombus ) = 4 × side

  • Here, perimeter is given 32 Cm. comparing the formula with the perimeter.

Therefore,

⇝4 × side = 32 cm

⇝side = 32/4

⇝side = 8 m

Hence, side of rhombus is 8 cm.

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❑ Now finding attitude of the rhombus.

  • Area of the rhombus is given which is 72 cm²

Therefore,

72 = 8 × Altitude

Altitude = 72/8

Altitude = 9 cm

Answered by XxRedmanherexX
2

Given:-

The ratio of the corresponding sides of two similar triangles is 3:5.

Solution:-

Let the ratio of corresponding sides of two similar triangles be side 1 : Side 2 = 3 : 5 .

And let the ratio of areas of two similar triangles is Area 1 : Area 2.

Now as we know that if two triangles similar, then the ratio of areas is equal to the ratio of squares of corresponding sides.

so,

➟Area 1 / Area 2 = ( Side 1 /side 2 )²

➟Area 1 / Area 2 = (3/5)²

➟Area 1 / Area 2 =9/25

•°•➩9/25

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