The area of a rhombus is 72 cm². If the perimeter is 32 cm, find its altitude.
Answers
Given: the area of a rhombus is 72 cm². And the Perimeter is 32 Cm.
Need to find : The altitude of the rhombus.
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As we know that :-
Perimeter ( rhombus ) = 4 × side
- Here, perimeter is given 32 Cm. comparing the formula with the perimeter.
Therefore,
⇝4 × side = 32 cm
⇝side = 32/4
⇝side = 8 m
Hence, side of rhombus is 8 cm.
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❑ Now finding attitude of the rhombus.
- Area of the rhombus is given which is 72 cm²
Therefore,
⇝72 = 8 × Altitude
⇝Altitude = 72/8
⇝Altitude = 9 cm✯
Given:-
The ratio of the corresponding sides of two similar triangles is 3:5.
Solution:-
Let the ratio of corresponding sides of two similar triangles be side 1 : Side 2 = 3 : 5 .
And let the ratio of areas of two similar triangles is Area 1 : Area 2.
Now as we know that if two triangles similar, then the ratio of areas is equal to the ratio of squares of corresponding sides.
so,
➟Area 1 / Area 2 = ( Side 1 /side 2 )²
➟Area 1 / Area 2 = (3/5)²
➟Area 1 / Area 2 =9/25
•°•➩9/25