Math, asked by nehaperween8207, 10 months ago

The area of a rhombus is 88cms and one of its diagonals is
11cm. The second diagonals will be -​

Answers

Answered by VishnuNandan
1

Answer:

area of shombus = d^2/2

so 11×x/2=88

11x=88/2=44

x= 44/11 =4

Answered by Meghal28
1

Step-by-step explanation:

area=88

1 diagonal=11

area of rhombus=1/2×d1+d2

88=1/2×11+d2

44/11=d2

4cm=d2

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