the area of a rhombus is 960 cmsquare. if one of the diagonals is 32 CM, then find the other diagonal
Answers
Step-by-step explanation:
Given
One Diagonal ⇒ 32 cm
Area of Rhombus ⇒ 960 cm²
________________________________
To Find
The measure of the other diagonal.
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Solution
Area of Rhombus ⇒ 960 cm²
Area of Rhombus ⇒ Diagonal 1 × Diagonal 2 × ¹/₂
Diagonal 1 ⇒ 32 cm
Diagonal 2 ⇒ x cm
Equation to find Diagonal 2 ⇒ 32 × x × ¹/₂ = 960
Let's solve your equation step-by-step.
32\times x \times \dfrac{1}{2} = 96032×x×
2
1
=960
Step 1: Simplify the equation.
⇒ 32\times x \times \dfrac{1}{2} = 96032×x×
2
1
=960
⇒ 32x \times \dfrac{1}{2} = 96032x×
2
1
=960
Step 2: Multiply 2 from both sides of the equation.
⇒ 32x \times \dfrac{1}{2} \times 2 = 960\times 232x×
2
1
×2=960×2
⇒ 32x = 192032x=1920
Step 3: Divide 32 from both sides of the equation.
⇒ \dfrac{32x}{32} = \dfrac{1920}{32}
32
32x
=
32
1920
⇒ x = 60x=60
Nice yo meet you yadav myself varsha yadav :)
Answer:
Area of Rhombus = 1/2(product of diagonals).
Given one diagonal as 32 cm.
let us take the other diagonal as x.
then 1/2(32*x)=960
32*x=960*2
x=960*2/32
32*30=960
then cancel 960 to 32
then 30*2=60