Math, asked by lovelyyadav1607, 21 days ago

the area of a rhombus is 960 cmsquare. if one of the diagonals is 32 CM, then find the other diagonal​

Answers

Answered by nithya12333
4

Step-by-step explanation:

Given

One Diagonal ⇒ 32 cm

Area of Rhombus ⇒ 960 cm²

________________________________

To Find

The measure of the other diagonal.

________________________________

Solution

Area of Rhombus ⇒ 960 cm²

Area of Rhombus ⇒ Diagonal 1 × Diagonal 2 × ¹/₂

Diagonal 1 ⇒ 32 cm

Diagonal 2 ⇒ x cm

Equation to find Diagonal 2 ⇒ 32 × x × ¹/₂ = 960

Let's solve your equation step-by-step.

32\times x \times \dfrac{1}{2} = 96032×x×

2

1

=960

Step 1: Simplify the equation.

⇒ 32\times x \times \dfrac{1}{2} = 96032×x×

2

1

=960

⇒ 32x \times \dfrac{1}{2} = 96032x×

2

1

=960

Step 2: Multiply 2 from both sides of the equation.

⇒ 32x \times \dfrac{1}{2} \times 2 = 960\times 232x×

2

1

×2=960×2

⇒ 32x = 192032x=1920

Step 3: Divide 32 from both sides of the equation.

⇒ \dfrac{32x}{32} = \dfrac{1920}{32}

32

32x

=

32

1920

⇒ x = 60x=60

Nice yo meet you yadav myself varsha yadav :)

Answered by nktulo665
1

Answer:

Area of Rhombus = 1/2(product of diagonals).

Given one diagonal as 32 cm.

let us take the other diagonal as x.

then 1/2(32*x)=960

32*x=960*2

x=960*2/32

32*30=960

then cancel 960 to 32

then 30*2=60

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