Question

the area of a rhombus is 966sq cm.if the length of one of its diagnals is 46cm find the length of other diagnal​

Answer 1

Answer:

let the other rhombus be y

Area of Rhombus = 1/2(product of it's diagonals)

966sq cm = 1/2 ( y × 46)

966×2 = y×46

1932 = y × 46

1932/46 = y

42 = y

verify

LHS = RHS

Area of rhombus = 1/2(product of its diagonals

966 =1/2(42×46)

966 = 1/2×1932

966 = 966

proved

thank you

myself Ashakiran

Answer 2

Step-by-step explanation:

Area of rhombus = 1/2 × D1 × D2

= 966 = 1/2 × 46 × x

= 966 = 23x

x = 966/23

x = 42 cm

Hence length of other diagonal is 42 cm.

Hope it helps u

Mark as brainlest please