Math, asked by Rashul0515, 8 months ago

The area of a rhombus is 96cm^2. If its one diagonal is 12cm, find the length of its side​

Answers

Answered by aditya8443
3

Answer:

area of Rhombus =96m^2

1/2d^1×d^2 =96m^2

d^2 = 16m

d^1=d/2=6m

d^2=d/2=8m

diagonal of the rhombus is perpendicular bisecter

AOC =right angle triangle

AB ^2=AO^2 +OB^2

AB^2 = 36+64

AB^2=100

AB=10cm

side of Rhombus =10 centimeters

Answered by rajukorrapaduchethan
0

Answer:

16

Step-by-step explanation:

  1. the area of rhombus is 1/2d1d2 so one diagonal is 12cm then area of rhombus is 96cm answer is 1/2×12×x=96 then 6x= 96 that x= 16 length of diagonal = length of side
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