The area of a rhombus is 96cm^2. If its one diagonal is 12cm, find the length of its side
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Answered by
3
Answer:
area of Rhombus =96m^2
1/2d^1×d^2 =96m^2
d^2 = 16m
d^1=d/2=6m
d^2=d/2=8m
diagonal of the rhombus is perpendicular bisecter
AOC =right angle triangle
AB ^2=AO^2 +OB^2
AB^2 = 36+64
AB^2=100
AB=10cm
side of Rhombus =10 centimeters
Answered by
0
Answer:
16
Step-by-step explanation:
- the area of rhombus is 1/2d1d2 so one diagonal is 12cm then area of rhombus is 96cm answer is 1/2×12×x=96 then 6x= 96 that x= 16 length of diagonal = length of side
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