Question

The area of a rhombus is 96cm square. If one of its diagonals are 12
cm, then find the length of its sides ?

Answer 1

Area of the rhombus = d1xd2/2

96 =12xd2/2

96x2=12xd2

96x2/12=d2

8x2=d2

16=d2

Answer 2

Area of rhombus = 96cm sq
Let the given diagona l be a and are be A and the other diagonal be b
then A = ab/ 2
96 = 12 × b/ 2
b = 96 × 2 / 12
b = 16 cm
to find the Sides of rhombus we have the formula
S = underroot of a^ 2 + b^2 /2
S = underroot of 12^2 + 16^2 /2
S = underroot of 144 + 256 / 2
S = underroot of 400 / 2
S = 20/2
S = 10cm