The area of a rhombus is equal to the area of a triangle having base 24.8 cmand the corresponding hight 16.5 cm. If one of the diagonal of the rhombus is 22 cm, find the length of the other diagonal.
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18.6
plz give thnx
it is absolutely correct answer
plz give thnx
it is absolutely correct answer
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area of triangle PQR = 1/2× 24.8×16.5 cm^2
=204.6cm^2
area of rhombus ABCD = 1/2× product of diagonals
diagonal 1 = 22 cm
let diagonal 2 be x cm
according to the question,
area of rhombus ABCD = area of triangle PQRS
=>1/2×22×x=204.6
=>x=(204.6×2)/22
=>x=18.6
so length of another diagonal of rhombus =18.6 cm
=204.6cm^2
area of rhombus ABCD = 1/2× product of diagonals
diagonal 1 = 22 cm
let diagonal 2 be x cm
according to the question,
area of rhombus ABCD = area of triangle PQRS
=>1/2×22×x=204.6
=>x=(204.6×2)/22
=>x=18.6
so length of another diagonal of rhombus =18.6 cm
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